#P110B. Lucky String

    ID: 6676 远端评测题 2000ms 256MiB 尝试: 0 已通过: 0 难度: (无) 上传者: 标签>constructive algorithmsstrings*1100

Lucky String

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Description

Petya loves lucky numbers. We all know that lucky numbers are the positive integers whose decimal representations contain only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.

Petya recently learned to determine whether a string of lowercase Latin letters is lucky. For each individual letter all its positions in the string are written out in the increasing order. This results in 26 lists of numbers; some of them can be empty. A string is considered lucky if and only if in each list the absolute difference of any two adjacent numbers is a lucky number.

For example, let's consider string "zbcdzefdzc". The lists of positions of equal letters are:

  • b: 2
  • c: 3, 10
  • d: 4, 8
  • e: 6
  • f: 7
  • z: 1, 5, 9
  • Lists of positions of letters a, g, h, ..., y are empty.

This string is lucky as all differences are lucky numbers. For letters z: 5 - 1 = 4, 9 - 5 = 4, for letters c: 10 - 3 = 7, for letters d: 8 - 4 = 4.

Note that if some letter occurs only once in a string, it doesn't influence the string's luckiness after building the lists of positions of equal letters. The string where all the letters are distinct is considered lucky.

Find the lexicographically minimal lucky string whose length equals n.

The single line contains a positive integer n (1 ≤ n ≤ 105) — the length of the sought string.

Print on the single line the lexicographically minimal lucky string whose length equals n.

Input

The single line contains a positive integer n (1 ≤ n ≤ 105) — the length of the sought string.

Output

Print on the single line the lexicographically minimal lucky string whose length equals n.

Samples

5

abcda

3

abc

Note

The lexical comparison of strings is performed by the < operator in modern programming languages. String a is lexicographically less than string b if exists such i (1 ≤ i ≤ n), that ai < bi, and for any j (1 ≤ j < i) aj = bj.